document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=871076>Question 871076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 26.	Martina leaves home at 9 AM, bicycling at a rate of 24 mph. Two hours later, John leaves, driving at 48 mph. At what time will John catch up with Martina?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525299 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Martina leaves home at 9 AM, bicycling at a rate of 24 mph. Two hours later, John leaves, driving at 48 mph. At what time will John catch up with Martina? <BR>\n" );
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document.write( "let x= travel time of Martina<BR>\n" );
document.write( "x-2=travel time of john<BR>\n" );
document.write( "distance=travel time*speed<BR>\n" );
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document.write( "24x=48(x-2)<BR>\n" );
document.write( "24x=48x-96<BR>\n" );
document.write( "24x=96<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "John will catch up with Martina ln 4 hrs at 1 PM </SPAN>\n" );
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