document.write( "Question 871050: While traveling to and from a certain destination, you realized increasing your speed by 10 mph saved 1 hours on your return. If the total distance of the roundtrip was 600 miles, find the speed driven while returning. \n" ); document.write( "
Algebra.Com's Answer #525286 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed to go there x \n" ); document.write( "speed returning x + 10 \n" ); document.write( " \n" ); document.write( "Distance = same 300 km \n" ); document.write( "original time – time with increased speed = 1 hour \n" ); document.write( "t=d/t \r \n" ); document.write( "\n" ); document.write( "300 / x - 300 / ( x + 10 ) = 1 \n" ); document.write( "LCD= x ( x + 10 ) \n" ); document.write( "multiply by LCD \n" ); document.write( "300 ( x + 10 ) - 300 x = 1 x ( x + 10 ) \n" ); document.write( "300 x + 3000 - 300 x = 1 X^2 + 10 x \n" ); document.write( "3000 = 1 X^2 + 10 x \n" ); document.write( "1 X^2 + 10 x - -3000 = 0 \n" ); document.write( "Find roots of the quadratic equation \n" ); document.write( "a= 1 b= 10 c= -3000 \n" ); document.write( " \n" ); document.write( "x1= ( -10 + sqrt( 100 - 12000 )) / 2 \n" ); document.write( "x1=( -10 + 110 )/ 2 \n" ); document.write( "x1= 50 \n" ); document.write( " \n" ); document.write( "x2= ( -7 - sqrt( 49 - 20 ) / 2 \n" ); document.write( "x2=( -10 - 110 )/ 2 \n" ); document.write( "x2= -60 ignore negative value\r \n" ); document.write( "\n" ); document.write( "to go there speed = 50 mph\r \n" ); document.write( "\n" ); document.write( "returning speed = 60 mph \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |