document.write( "Question 871059: A mixture of 4% disinfectant solution is to be made from 8% and 2% disinfectant solutions. How much of each solution should be used if 33 gallons of 4% solution are needed?
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Algebra.Com's Answer #525283 by mananth(16946)\"\" \"About 
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Percent ---------------- quantity
\n" ); document.write( "disinfectant I 8.00% ---------------- x gallons
\n" ); document.write( "disinfectant II 2.00% ------ 33 - x gallons
\n" ); document.write( "Mixture 4.00% ---------------- 33
\n" ); document.write( "Total 33 gallons
\n" ); document.write( "8.00% x + 2.00% ( 33 - x ) = 4.00% * 33
\n" ); document.write( "8 x + 2 ( 33 - x ) = 132
\n" ); document.write( "8 x + 66 - 2 x = 132
\n" ); document.write( "8 x - 2 x = 132 - -66
\n" ); document.write( "6 x = 66
\n" ); document.write( "/ 6
\n" ); document.write( " x = 11 gallons 8.00% disinfectant I
\n" ); document.write( " 22 gallons 2.00% disinfectant II
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\n" ); document.write( "m.ananth@hotmail.ca
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