document.write( "Question 73404This question is from textbook
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document.write( ": 1. 3x + y = 6
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document.write( " x - y = 1\r
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document.write( "2. If x Varies directly as y^2, and x= 20 when y= 2, find x when y= 10. \n" );
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Algebra.Com's Answer #52526 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( " 3x + y = 6\r\n" ); document.write( " x - y = 1\r\n" ); document.write( " \n" ); document.write( "Add the 2 equations. Add 3x to x, y to -y, and 6 to 1 \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 4x = 7\r\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "Now solve for x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Plug this into \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Check: \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 3(7/4) + 3/4 = 6\r\n" ); document.write( " 7/4 - 3/4 = 1\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 21/4 + 3/4 = 6\r\n" ); document.write( " 4/4 = 1\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 24/4 = 6\r\n" ); document.write( " 1=1 Works\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 6 = 6 Works\r\n" ); document.write( " 1 = 1 Works\r\n" ); document.write( " \n" ); document.write( " \r |