document.write( "Question 871008: Find the solutions in the interval [0, 2pi)\r
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document.write( "2 cos 3x = 1\r
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document.write( "This is due tomorrow and I am very confused, any and all help is greatly appreciated :) \n" );
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Algebra.Com's Answer #525258 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "The cosine function takes all the positive values between 0 and 1, without repeating in quadrant I and again in quadrant IV. \n" ); document.write( "In quadrants II and III cosine has negative values. \n" ); document.write( "In quadrant I (between 0 and \n" ); document.write( "we have \n" ); document.write( "In quadrant IV , \n" ); document.write( "Since cosine has a period of \n" ); document.write( "So all the angles with a cosine of \n" ); document.write( " \n" ); document.write( "If \n" ); document.write( " \n" ); document.write( "The solutions in the interval \n" ); document.write( " |