document.write( "Question 870964: At 9:30, a car A started its journey and travelled at 65 km/h. At 11:00, car B started its journey from the same place and travelled on the same road as car A. If car B, travelling at a constant speed, took five hours to catch up with car A, find the speed of car B. \n" ); document.write( "
Algebra.Com's Answer #525243 by mananth(16946)\"\" \"About 
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Car A 65 km/h
\n" ); document.write( "Car B x km/h
\n" ); document.write( "Car A 09:30
\n" ); document.write( "Car B 11:00
\n" ); document.write( "Difference in time= 01:30 => 1.50 hours
\n" ); document.write( "Car A will have covered 97.50 miles when Car B starts
\n" ); document.write( "catch up distance= 97.50 miles
\n" ); document.write( "catch up speed = x -65
\n" ); document.write( "catch up time = 5 hours\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "5=97.50/(x-65)\r
\n" ); document.write( "\n" ); document.write( "5x-325=97.50
\n" ); document.write( "5x=325+97.50
\n" ); document.write( "5x=422.50
\n" ); document.write( "/5
\n" ); document.write( "x=84.62 km/h-------------Car B\r
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