document.write( "Question 73363: Clyde has 26 coins altogether consisting of dimes and nickels. If he receives 2 more nickels but loses on third of his dimes, he will have $1.70. How many dimes does he start with? \n" ); document.write( "

Algebra.Com's Answer #52521 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x= number of dimes\r
\n" ); document.write( "\n" ); document.write( "Then 26-x=number of nickels\r
\n" ); document.write( "\n" ); document.write( "He receives 2 more nickels--------------(26-x)+2=(28-x)
\n" ); document.write( "He loses 1/3 of his dimes ------------------x-(1/3)x=(2/3)x
\n" ); document.write( "so:
\n" ); document.write( "Now lets deal in pennies
\n" ); document.write( "5(28-x)+10((2/3)x)=170 simplify\r
\n" ); document.write( "\n" ); document.write( "140-5x+(20/3)x=170 Multiply both sides by 3\r
\n" ); document.write( "\n" ); document.write( "420-15x+20x=510 subtract 420 from both sides
\n" ); document.write( "-15x+20x=510-420 collect like terms
\n" ); document.write( "5x=90 divide both sides by 5
\n" ); document.write( "x=18-----------------------------------------------number of dimes\r
\n" ); document.write( "\n" ); document.write( "26-x=26-18=8------------------------------------number of nickels\r
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\n" ); document.write( "\n" ); document.write( "ck\r
\n" ); document.write( "\n" ); document.write( "receives 2 more nickels---------------8+2=10
\n" ); document.write( "Loses 1/3 of his dimes-------18-18/3=18-6=12 dimes\r
\n" ); document.write( "\n" ); document.write( "10*5+12*10=170
\n" ); document.write( "50+120=170
\n" ); document.write( "170=170\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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