document.write( "Question 870652: The 3 boys found 20.30 dollars in their brother's old money box, and were given
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document.write( "precise instructions as to how it should be shared out.
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document.write( "Ron was to get one and a third times as much as Paul, but one and a half times as much as Jack.
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document.write( "How much for Ron? \n" );
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Algebra.Com's Answer #525196 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! r = Rods's share \n" ); document.write( "p = Paul's share \n" ); document.write( "j = Jack's share \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement. We want to get p and j in terms of r \n" ); document.write( ": \n" ); document.write( "The 3 boys found 20.30 dollars in their brother's old money box, \n" ); document.write( "r + p + j = 20.30 \n" ); document.write( ": \n" ); document.write( "Ron was to get one and a third times as much as Paul, \n" ); document.write( "r = 1 \n" ); document.write( "r = \n" ); document.write( "Mult by 3 \n" ); document.write( "3r = 4p \n" ); document.write( "p = \n" ); document.write( ": \n" ); document.write( " but one and a half times as much as Jack. \n" ); document.write( "r = 1 \n" ); document.write( "r = \n" ); document.write( "mult by 2 \n" ); document.write( "2r = 3j \n" ); document.write( "j = \n" ); document.write( ": \n" ); document.write( "r + p + j = 20.30 \n" ); document.write( "replace p and j \n" ); document.write( "r + \n" ); document.write( "mult by 12, cancel the denominators \n" ); document.write( "12r + 3(3r) + 4(2r) = 12(20.30) \n" ); document.write( "12r + 9r + 8r = 243.6 \n" ); document.write( "29r = 243.6 \n" ); document.write( "r = \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can confirm this for yourself, find p and j see if they add up to 20.30 \n" ); document.write( " |