document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=870828>Question 870828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> URGENT HELP NEEDED! PLEASE SHOW WITH WORKINGS!<BR>\n" );
document.write( "A regular hexagon is circumscribed about a circle with a radius of 3 cm with centre O. <BR>\n" );
document.write( "(a) What is angle EOD?<BR>\n" );
document.write( "(b) Find the area of triangle EOD and hence find the area of the hexagon ABCDEF. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525192 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> note that a hexagon has 6 sides and made up of 6 equalaterial triangles<BR>\n" );
document.write( "a) angle EOD = 360 / 6 = 60 degrees<BR>\n" );
document.write( "b) divide one of the equilateral triangles in half and we get a 30, 60, 90 right triangle.  we know the altitute of the new triangle is 3 cm and we can calculate its base by tan(60) = altitude / base = 3 / base and<BR>\n" );
document.write( "base = 3 / tan(60) = 1.73 cm, therefore the area of the new triangle is<BR>\n" );
document.write( "area = (1/2)*(1.73)*3 = 2.60 cm^2<BR>\n" );
document.write( "now the area of EOD is 2 * 2.60 = 5.2 cm^2, and<BR>\n" );
document.write( "area of ABCDEF is 6*(5.2) = 31.2 cm^2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );