document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=870852>Question 870852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a businesswoman invested 6000$; part of it a 8% and the rest at 12%. If the total interest in one year is $560, find the amount she invested at each rate of interest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525191 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .12x + .08($6000-x) = $560<BR>\n" );
document.write( "     x = 80/.04 = $2000 at 12%, $4000 at 8% </SPAN>\n" );
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