document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=870819>Question 870819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y^2=-4y+2x+1 <BR>\n" );
document.write( "1. how do you write in standard form<BR>\n" );
document.write( "2. and what will the graph look like<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525182 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2=-4y+2x+1 <BR>\n" );
document.write( "y^2+4y= 2x+1 <BR>\n" );
document.write( "(y+2)^2 = 2x + 1 + 4<BR>\n" );
document.write( "(y+2)^2 = 2x + 5<BR>\n" );
document.write( "0r<BR>\n" );
document.write( " x = (1/2)(y+2)^2 -5/2   4p = 2, p = .5<BR>\n" );
document.write( "Parabola Opening right V(-2.5, -2) line of symmetry:  y = -2<BR>\n" );
document.write( "focus (-2, -2) directrix = x = -3 </SPAN>\n" );
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