document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=870776>Question 870776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hypotenuse 50mm 14mm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #525148 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=525148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is not enough information here.<BR>\n" );
document.write( "If you are asking for the other leg of a right triangle when one leg is 14mm and the hypotenuse is 50mm, then:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14%5E2+%2B+y%5E2+=+50%5E2 ALIGN=MIDDLE  ALT=\"14%5E2+%2B+y%5E2+=+50%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "196 + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2 ALIGN=MIDDLE  ALT=\"y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 2500<BR>\n" );
document.write( "Subtract 196 from each side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2 ALIGN=MIDDLE  ALT=\"y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >= 2304<BR>\n" );
document.write( "Sq rt each side<BR>\n" );
document.write( "y = 48 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );