document.write( "Question 870783: Please help....I cannot help my son with this question.
\n" ); document.write( "What is the equation of the quadratic graph with a focus of (6,0) and a directrix of y=-10?
\n" ); document.write( "Please explain, if possible how to work this kind of a problem. Thank you so much!!!
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Algebra.Com's Answer #525144 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Horizontal Directrix: y = -10, Parabola Opens Upward (Focus above it)
\n" ); document.write( "F(6,0)
\n" ); document.write( "(0-10)/2 = -5 V(6, -5), p = 5
\n" ); document.write( "y = (1/4p)(x - 6)^2 - 5
\n" ); document.write( "y = (1/20)(x - 6)^2 - 5
\n" ); document.write( "the vertex form of a Parabola opening up(a>0) or down(a<0), \"y=a%28x-h%29%5E2+%2Bk\"
\n" ); document.write( "where(h,k) is the vertex and x = h is the Line of Symmetry. a = 1/4p
\n" ); document.write( "where the focus is (h,k + p)
\n" ); document.write( "With Directrix y = (k - p)
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