document.write( "Question 73352: the fuel tank in a car was 40% full. i added 28 litres and then found it was 75% full. how much fuel does the tank hold?
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Algebra.Com's Answer #52512 by bucky(2189)\"\" \"About 
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Let x be the amount of gas the tank holds when full. Then all you need to do is write the
\n" ); document.write( "equation for the situation before you started. That situation was that the tank was 40% (decimal 0.4)
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\n" ); document.write( "So before you started you had 0.4*x litres in the tank representing 40% of a full tank.
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\n" ); document.write( "Next you added 28 litres to that amount giving you what you started with plus 28 litres.
\n" ); document.write( "So now the tank has in it:
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\n" ); document.write( "0.4*x + 28
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\n" ); document.write( "But you then find that this amount is 75% (decimal 0.75) of a full tank. This can be written
\n" ); document.write( "as 0.75*x.
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\n" ); document.write( "Set the two equal to get:
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\n" ); document.write( "0.4x + 28 = 0.75*x
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\n" ); document.write( "Subtract 28 litres from both sides to eliminate the 28 litres from the left side and get:
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\n" ); document.write( "0.4*x = 0.75x - 28
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\n" ); document.write( "Now subtract 0.75*x from both sides to eliminate the 0.75*x from the right side. This subtraction
\n" ); document.write( "results in:
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\n" ); document.write( "-0.35*x = -28
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\n" ); document.write( "Now just divide both sides by -0.35 and you find that:
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\n" ); document.write( "x = -28/-0.35 = 80 litres
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\n" ); document.write( "When the tank is full it contains 80 litres.
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\n" ); document.write( "When you started the tank had 40% of 80 litres or it had 32 litres. You added 28 litres
\n" ); document.write( "and then the tank had 60 litres in it (32 plus 28). And this 60 litres was 75% or 3/4 of
\n" ); document.write( "a full tank. All the figures check, so it looks as if our answer is correct.
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\n" ); document.write( "Hope this helps you to understand the problem a little better.
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