document.write( "Question 870642: log(x)+log(x+3)=log(10) \n" ); document.write( "
Algebra.Com's Answer #525011 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! log(x)+log(x+3)=log(10)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(x*(x+3))=log(10)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10^[log(x*(x+3))]=10^[log(10)]\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x*(x+3) = 10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2+3x = 10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2+3x-10 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x + 5)(x - 2) = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5 = 0 or x - 2 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -5 or x = 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The domain of log(x) is x > 0, so we toss x = -5. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only solution is x = 2. \n" ); document.write( " |