document.write( "Question 870615: Solve the equation for solutions over the interval [0, 360). Give solutions to the nearest tenth as appropriate. \r
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document.write( "Cos^2(theta) = sin^2(theta) + 1 \n" );
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Algebra.Com's Answer #525008 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! First solve for theta\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos^2(theta) = sin^2(theta) + 1 \n" ); document.write( "cos^2(theta) - sin^2(theta) = 1 \n" ); document.write( "cos(2theta) = 1 \n" ); document.write( "2theta = arcos(1) \n" ); document.write( "2theta = 0+360*n \n" ); document.write( "2theta = 360*n \n" ); document.write( "theta = 360*n/2 \n" ); document.write( "theta = 180n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So theta = 180n generates all of the solutions for theta where n is an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If n = 0, then \n" ); document.write( "theta = 180n \n" ); document.write( "theta = 180*0 \n" ); document.write( "theta = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If n = 1, then \n" ); document.write( "theta = 180*n \n" ); document.write( "theta = 180*1 \n" ); document.write( "theta = 180\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If n = 2, then \n" ); document.write( "theta = 180*n \n" ); document.write( "theta = 180*2 \n" ); document.write( "theta = 360 ... toss this solution since it's not in the interval [0, 360)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==============================================================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only two solutions are theta = 0, theta = 180 (both in degrees) \n" ); document.write( " \n" ); document.write( " |