document.write( "Question 870607: A new type of light bulb has an average lifespan of 1200 hours with a standard deviation of 75 hours
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document.write( "Use the table to find out the probability that a lightbulb chosen at random will last 1140-1260 hours \n" );
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Algebra.Com's Answer #524979 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Convert the raw score of x = 1140 to a standard z-score\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x-mu)/sigma \n" ); document.write( "z = (1140-1200)/75 \n" ); document.write( "z = -0.80\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use this table to find the area to the left of z = -0.80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That area is 0.2119. Let's call this area1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Convert the raw score of x = 1260 to a standard z-score\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x-mu)/sigma \n" ); document.write( "z = (1260-1200)/75 \n" ); document.write( "z = 0.80\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use this table to find the area to the left of z = 0.80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That area is 0.7881. Let's call this area2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now subtract the two areas: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area2 - Area1 = 0.7881 - 0.2119 = 0.5762\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area between z = -0.80 and z = 0.80 is approximately 0.5762\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the area between x = 1140 and x = 1260 is also approximately 0.5762\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That means the probability is about 0.5762 (roughly 57.62%) \n" ); document.write( " \n" ); document.write( " |