document.write( "Question 870379:  Here is the question: Sandy left the city for vacation. Sam left 6 hours later going 75 mph faster to catch up. After 5 hours Sam caught up. What was Sandy's average speed?\r
\n" );
document.write( "\n" );
document.write( "I have made a chart to try to solve, but as we have not studied this time of d=rt I am unable to solve it. Thank you for any help. \n" );
document.write( "
| Algebra.Com's Answer #524955 by Fombitz(32388)     You can put this solution on YOUR website! It took Sandy 11 hours to ttravel the same distance that Sam took 5 hours. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |