document.write( "Question 870306: Light Bulbs have an advertised rating of 1750 lumens. If measurements are normally distributed with mean 1784 and standard deviation 38, what percentage of bulbs exceed the advertised rating? \n" ); document.write( "

Algebra.Com's Answer #524800 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "z = (1750-1784)/38 = -34/38 = -.8974
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document.write( "P(x > 1750) = P(z > -.8974) = 81.52 %
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document.write( "use z-table or Calculator to find P(z ≥ -.8974) 
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document.write( "TI syntax is normalcdf(smaller z, larger z).
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document.write( "P(z > -.8974) = normalcdf(-.8974, 10)   | z= 10 being a placeholder \n" );
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