document.write( "Question 870128: 2/3x - 5/6y\r
\n" ); document.write( "\n" ); document.write( "I got 12y/6y - 15/6y= 12-5/6y= 2-5/y\r
\n" ); document.write( "\n" ); document.write( "Is that correct?
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Algebra.Com's Answer #524721 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
2/3x - 5/6y\r
\n" ); document.write( "\n" ); document.write( "I got 12y/6y - 15/6y= 12-5/6y= 2-5/y
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\n" ); document.write( "The DEN has to have an x & a y.
\n" ); document.write( "2/3x - 5/6y
\n" ); document.write( "Find a common denominator. The product always works
\n" ); document.write( "= 18xy
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\n" ); document.write( "--> 2*6y/DEN - 5*3x/DEN
\n" ); document.write( "= (12y - 15x)/18xy
\n" ); document.write( "= (4y - 5x)/6xy
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