document.write( "Question 870136: One solution is 60% acid and another is 15% how much would be needed of each to make 300 L at 50% acid if someone could show me how to figure out the answer it would be great \n" ); document.write( "

Algebra.Com's Answer #524684 by lwsshak3(11628) $\"\"$ $\"About$

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One solution is 60% acid and another is 15% how much would be needed of each to make 300 L at 50% acid.
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\n" ); document.write( "let x=amt of 60% solution needed
\n" ); document.write( "300-x=amt of 15% solution needed
\n" ); document.write( "60%x+15%(300-x)=50%*300
\n" ); document.write( ".60x+45-.15x=150
\n" ); document.write( ".45x=105
\n" ); document.write( "x=105/.45
\n" ); document.write( "x≈233.33 L
\n" ); document.write( "300-x≈66.66 L
\n" ); document.write( "amt of 60% solution needed≈233.33 L
\n" ); document.write( "amt of 15% solution needed≈66.66 L \n" ); document.write( "

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