document.write( "Question 870014: A company claimed to randomly choose a committee of three employees to represent the employees at a bargaining session. Of the 50 employees from whom the committee was chosen, 20 are female and 30 are male. The committee turned out to be all male.\r
\n" ); document.write( "\n" ); document.write( "Determine the probability the committee of three would include at least one female, if the selection were truly random. \n" ); document.write( "
Algebra.Com's Answer #524672 by Theo(13342)\"\" \"About 
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The probability that the committee of 3 would consist of all 3 men is equal to:\r
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\n" ); document.write( "\n" ); document.write( "30/50 * 29/49 * 28/48 = .2071\r
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\n" ); document.write( "\n" ); document.write( "The probability that at least one of the committee members would be female is equal to:\r
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\n" ); document.write( "\n" ); document.write( "1 - .2071 = .7929\r
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\n" ); document.write( "\n" ); document.write( "round these answers to 2 decimal places and you get:\r
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\n" ); document.write( "\n" ); document.write( "p(all males) = .21
\n" ); document.write( "p(at least 1 female) = .79\r
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