document.write( "Question 73196: During rush hour, Fernando can drive 35 miles using the side roads in the same time that it takes to travel 30 miles on the freeway. If Fernando’s rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads. \n" ); document.write( "
Algebra.Com's Answer #52467 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x=rate on freeway \n" ); document.write( "Then (x+9)=rate on side roads\r \n" ); document.write( "\n" ); document.write( "distance(d)=rate(r) times time(t) or d=rt and t=d/r\r \n" ); document.write( "\n" ); document.write( "time to drive 35 mi using side roads= \n" ); document.write( "And time to drive 30 miles using freeway= \n" ); document.write( "\n" ); document.write( "Now we are told that the above two times are equal, so:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "t=d/r \n" ); document.write( "35/63=30/54 \n" ); document.write( "0.55555=0.55555\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |