document.write( "Question 870024: I read through Question 869777, but did not understand the response given to it, is there perhaps another way of wording it? I appreciate the answer supplied, but can't seem to wrap my head around the concept\r
\n" ); document.write( "\n" ); document.write( "Can you help me to solve the following question:
\n" ); document.write( "The vertical displacement of the end of a robot arm (in mm) at time t (in seconds) is given by
\n" ); document.write( "y=1+4cos(2t)-4sin(4t)
\n" ); document.write( "a) find all times, t>0 (in exact form i.e. in terms of pi) where the vertical displacement is 1mm, i.e. y=1
\n" ); document.write( "b) what is the first time, t>0 that the vertical displacement is 1mm? give you answer exactly and to 2 decimal places?
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Algebra.Com's Answer #524651 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"y=1%2B4cos%282t%29-4sin%284t%29=1%2B4\"\"%22%5B%22\"\"cos%282t%29-sin%284t%29\"\"%22%5D%22\" is a periodic function, waving above and below \"y=1\" , whose graph looks like this:
\n" ); document.write( "\"graph%28600%2C300%2C-1.6%2C6.4%2C-7%2C9%2C1%2B4cos%282x%29-4sin%284x%29%2C1%29\" Its period is \"pi\" because at \"t\" and \"t%2Bpi\" the function has the same \"y\" value:
\n" ); document.write( "\"y=1%2B4cos%282t%2B2pi%29-4sin%284t%2B4pi%29=y=1%2B4cos%282t%29-4sin%284t%29\" .
\n" ); document.write( "The function will take the value \"y=1\" an infinite number of times.
\n" ); document.write( "For an answer to part a) we can list the first few in order and then write \", ...\" or we can write it as a formula.
\n" ); document.write( "Either way, it is not a simple answer.
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\n" ); document.write( "The double angle trigonometric identity
\n" ); document.write( "\"sin%282A%29=2sin%28A%29%2Acos%28A%29\" can be applied, with \"A=2t\" to get
\n" ); document.write( "\"y=1%2B4\"\"%22%5B%22\"\"cos%282t%29-2sin%282t%29cos%282t%29\"\"%22%5D%22\"
\n" ); document.write( "Taking out \"cos%282t%29\" as a common factor, we get
\n" ); document.write( "\"y=1%2B4\"\"%22%5B%22\"\"cos%282t%29%281-2sin%282t%29%29\"\"%22%5D%22\"
\n" ); document.write( "\"y=1%2B4%2Acos%282t%29%2A%281-2sin%282t%29%29\"
\n" ); document.write( "When will we have \"y=1\" ?
\n" ); document.write( "We have to solve
\n" ); document.write( "\"1=1%2B4%2Acos%282t%29%2A%281-2sin%282t%29%29\"<--->\"4%2Acos%282t%29%2A%281-2sin%282t%29%29=0\"
\n" ); document.write( "That will be true when one of those factors (either \"cos%282t%29\" or \"%281-2sin%282t%29%29\" ) is zero.
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\n" ); document.write( "\"cos%282t%29=0\" --> \"2t=pi%2F2\" or \"2t=3pi%2F2\" or anything you can get by adding \"2pi\" to a previous answer.
\n" ); document.write( "So \"t=pi%2F4\" or \"t=3pi%2F4\" or anything you can get by adding \"pi\" to a previous answer.
\n" ); document.write( "
\n" ); document.write( "\"1-2sin%282t%29=0\"<--->\"sin%282t%29=1%2F2\"<--->\"2t=pi%2F6\" or \"2t=5pi%2F6\" or anything you can get by adding \"2pi\" to a previous answer.
\n" ); document.write( "That means \"t=pi%2F12\" or \"t=5pi%2F12\" or anything you can get by adding \"pi\" to a previous answer.
\n" ); document.write( "
\n" ); document.write( "a) The list of times when \"y=0\" is
\n" ); document.write( "\"pi%2F12\"\"%22%2C%22\" \"pi%2F4=3pi%2F12\"\"%22%2C%22\" \"5pi%2F12\"\"%22%2C%22\" \"3pi%2F4=9pi%2F12\"\"%22%2C%22\" \"13pi%2F12=pi%2F12%2Bpi\"\"%22%2C%22\"\"%22...%22\" (and keep adding \"pi\" to previous answers).
\n" ); document.write( "You could state that the answers are
\n" ); document.write( "\"t=%28n%2B1%29pi%2F12\" , \"t=%28n%2B3%29pi%2F12\" , \"t=%28n%2B5%29pi%2F12\" , and \"t=%28n%2B9%29pi%2F12\" , for any non-negative integer \"n\" .
\n" ); document.write( "I could not think of a simple and elegant way to express that as one formula.
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\n" ); document.write( "b) The first time \"y=1\" happens when \"highlight%28t=pi%2F12=0.26%29\"
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