document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869966>Question 869966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sandra is 36 years old. her son is 14 years old. how many years ago was Sandra 3 times older than her son?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524600 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sandra is 36 years old. her son is 14 years old. how many years ago was Sandra 3 times older than her son?<BR>\n" );
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document.write( "Let the number of years be \"x\"::<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "36-x = 3(14-x)<BR>\n" );
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document.write( "36-x = 42-3x<BR>\n" );
document.write( "-x + 3x = 42-36<BR>\n" );
document.write( "2x = 6<BR>\n" );
document.write( "x = 3 years ago<BR>\n" );
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document.write( "Checking::<BR>\n" );
document.write( "36-3 = 3(14-3)<BR>\n" );
document.write( "33 = 3(11)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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