document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73216>Question 73216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the parimeter of length square root of 27, heigth square root of 75.  I think it's 3 times 3 times 3 added together and it's 3 times 5 times 5 added together, but I'm not sure. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52458 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p=2*sqrt27+2*sqrt75 if this is rectangle<BR>\n" );
document.write( "p=2*3*sqrt3+2*5*sqrt3<BR>\n" );
document.write( "p=6*sqrt3+10*sqrt3<BR>\n" );
document.write( "p=10*sqrt3<BR>\n" );
document.write( "p=10*1.732<BR>\n" );
document.write( "p=17.32 answer </SPAN>\n" );
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