document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869890>Question 869890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let (ax+b)/(x^2-1)=a/(x+1)+b/(x-1). Find a and b. <BR>\n" );
document.write( "This is from the Pre-Cal Conics, rotation of axes section.  Any help would be awesome. thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524549 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ?\r<BR>\n" );
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document.write( "The right hand side,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28a%2F%28x%2B1%29%29%28%28x-1%29%2F%28x-1%29%29+%2B+%28%28b%2F%28x-1%29%29%29%28%28x%2B1%29%2F%28x%2B1%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28a%28x-1%29%2Bb%28x%2B1%29%29%2F%28%28x%2B1%29%28x-1%29%29 ALIGN=MIDDLE  ALT=\"%28a%28x-1%29%2Bb%28x%2B1%29%29%2F%28%28x%2B1%29%28x-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28ax-a%2Bbx%2Bb%29%2F%28x%5E2-1%29 ALIGN=MIDDLE  ALT=\"%28ax-a%2Bbx%2Bb%29%2F%28x%5E2-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, the numerators of left and right are the same.  We started with the equality, so now just adjust numerators to same form and compare corresponding terms.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax%2Bb=ax-a%2Bbx%2Bb ALIGN=MIDDLE  ALT=\"ax%2Bb=ax-a%2Bbx%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax%2Bb=ax%2Bbx%2Bb-a ALIGN=MIDDLE  ALT=\"ax%2Bb=ax%2Bbx%2Bb-a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax%2Bb=%28a%2Bb%29x%2B%28b-a%29 ALIGN=MIDDLE  ALT=\"ax%2Bb=%28a%2Bb%29x%2B%28b-a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The way those correspond, <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=a%2Bb ALIGN=MIDDLE  ALT=\"a=a%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=b-a ALIGN=MIDDLE  ALT=\"b=b-a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "?<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=a%2B%28b-a%29 ALIGN=MIDDLE  ALT=\"a=a%2B%28b-a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0=b-a ALIGN=MIDDLE  ALT=\"0=b-a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=a ALIGN=MIDDLE  ALT=\"b=a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "b=b-(a+b)<BR>\n" );
document.write( "b=-a<BR>\n" );
document.write( "One possibility is, a=0 and b=0. </SPAN>\n" );
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