document.write( "Question 869875: Please help, sort of confused.
\n" ); document.write( "Suppose the average family of four washes an average of 2000 pounds of clothes a year. Assume the variable is normally distributed. Standard deviation of 187.5 pounds. A sample of 50 families is taken. Find two values so that there is a 99.9% chance that the mean falls between them. \n" ); document.write( "

Algebra.Com's Answer #524535 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "a = .001, a/2 = .0005  z = 3.29
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document.write( "ME = 3.29(187.5/sqrt(50) = 87.2
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document.write( "CI: 187.5- 87.2 > m < 187.50 + 87.2
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document.write( " ( 100.3, 274.7) \n" );
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