document.write( "Question 869847: A 10% chlorine mixture is to be mixed to 25% of chlorine mixture to obtain 30 gallon of 20 % how many gallons of each can be used ? \n" ); document.write( "
Algebra.Com's Answer #524477 by dkppathak(439)![]() ![]() You can put this solution on YOUR website! A 10% chlorine mixture is to be mixed to 25% of chlorine mixture to obtain 30 gallon of 20 % how many gallons of each can be used ? \n" ); document.write( "Answer \n" ); document.write( "let 10% chlorine mixture is X liters \n" ); document.write( "let 25% chlorine mixture is y liters \n" ); document.write( "as per given conditions \n" ); document.write( "0.1 X + 0.25 Y = 6 (1) \n" ); document.write( "X + Y =30 (2) by multiplying (2) by 0.1 \n" ); document.write( "0.1 X + 0.25 Y = 6 (3) \n" ); document.write( "0.1 x + 0.1 y = 3 (4) \n" ); document.write( "by subtracting \n" ); document.write( "0.15 y = 3 \n" ); document.write( "y =3/0.15 =300/15 =20 gallon \n" ); document.write( " X + Y = 30 \n" ); document.write( "X + 20 = 30 \n" ); document.write( "X =10 gallon \n" ); document.write( "Answer 10% chlorine mixture 10 gallon \n" ); document.write( "25% chlorine mixture should be 20 gallon\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |