document.write( "Question 869603: In testing the effects of a drug, the percentage of the drug in the blood stream was given by p = 0.090t – 0.015t^2, where t is the time (in hours) after the drug was administered.\r
\n" ); document.write( "\n" ); document.write( "a. What is the maximum number of hours that the drug is in blood?
\n" ); document.write( "b. How much of the drug is in the system after 15 minutes?
\n" ); document.write( "c. How long is at least 12 percent of the drug in the system?
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Algebra.Com's Answer #524453 by Fombitz(32388)\"\" \"About 
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a)Find t when p=0.
\n" ); document.write( "\"0.090t-0.015t%5E2=0\"
\n" ); document.write( "\"0.090t=0.015t%5E2\"
\n" ); document.write( "\"t=0.090%2F0.015\"
\n" ); document.write( "\"t=6\" hours
\n" ); document.write( "b) 15 minutes = 1/4 hour
\n" ); document.write( "\"p=0.090%281%2F4%29-0.015%281%2F16%29\"
\n" ); document.write( "\"p=0.0225-.0009375\"
\n" ); document.write( "\"p=0.0215625\"
\n" ); document.write( "c) \"graph%28300%2C300%2C-2%2C8%2C-1%2C2%2C0.090x-0.015x%5E2%29\"
\n" ); document.write( "Looks for the two points when \"p=0.12\"
\n" ); document.write( "\"0.090t-0.015t%5E2=0.12\"
\n" ); document.write( "\"-15t%5E2%2B90t-120=0\"
\n" ); document.write( "\"t%5E2-6t%2B8=0\"
\n" ); document.write( "\"%28t-2%29%28t-4%29=0\"
\n" ); document.write( "Two solutions: \"t=2\" and \"t=4\"
\n" ); document.write( "So the difference is how long the drug is above 12%.
\n" ); document.write( "\"DELTA=4-2=2\"\"hours\"
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