document.write( "Question 869812: What is the area of a triangle with a hypotenuse of 14 and a height of 12
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Algebra.Com's Answer #524442 by mananth(16946)\"\" \"About 
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hypotenuse = 14\r
\n" ); document.write( "\n" ); document.write( "one leg =12\r
\n" ); document.write( "\n" ); document.write( "apply Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "x^2+12^=14^2\r
\n" ); document.write( "\n" ); document.write( "x^2=14^2-12^2\r
\n" ); document.write( "\n" ); document.write( "x^2=196-144\r
\n" ); document.write( "\n" ); document.write( "x^2=52\r
\n" ); document.write( "\n" ); document.write( "x= +/-2sqrt(13)\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2 * leg 1*leg2\r
\n" ); document.write( "\n" ); document.write( "=\"%281%2F2%29+%2A+12%2A2sqrt%2813%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"12sqrt%2813%29%29\"
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