document.write( "Question 73204: I am having a lot of trouble with this problem. Any help would be appreciated
\n" ); document.write( "Solve for x: 7 + sqrt(2x-5) = 12
\n" ); document.write( "7 + sqrt(2x-5) = 12 -subtract 7 from both sides
\n" ); document.write( "(sqrt(2x-5)^2=5^2
\n" ); document.write( "2x-5+5=25 +5
\n" ); document.write( "2x/2=20/2 -> 10
\n" ); document.write( "check: 7 + sqrt(2(10)-5 =12 ->7 + sqrt(15)=12 ***this is where i get stuck, i dont think the answer is right
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Algebra.Com's Answer #52444 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve for x: 7 + sqrt(2x-5) = 12
\n" ); document.write( ":
\n" ); document.write( "7 + sqrt(2x-5) = 12 -subtract 7 from both sides
\n" ); document.write( ":
\n" ); document.write( "(sqrt(2x-5)^2=5^2
\n" ); document.write( ":
\n" ); document.write( "2x - 5 + 5 = 25 + 5
\n" ); document.write( "Right here you should have
\n" ); document.write( "2x = 30
\n" ); document.write( "x = 30/2
\n" ); document.write( "x = 15
\n" ); document.write( ":
\n" ); document.write( "Check:
\n" ); document.write( "7 + Sqrt(2(15) - 5) = 12
\n" ); document.write( "7 + Sqrt(25) = 12
\n" ); document.write( ":
\n" ); document.write( "Your method was right, just a small math error. But you checked your solution in
\n" ); document.write( "the original equation and found out. That's good \n" ); document.write( "
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