document.write( "Question 869793: if the numinator and denominatar of a fracrion is increased by 2 the fraction become 5/7 and if its denominator is decreased by 1 the fraction becomes 3/4 . find the fraction ? \n" ); document.write( "

Algebra.Com's Answer #524411 by ramkikk66(644) $\"\"$ $\"About$

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document.write( "if the numinator and denominatar of a fracrion is increased by 2 the fraction become 5/7 and if its denominator is decreased by 1 the fraction becomes 3/4 . find the fraction ?\r\n" );
document.write( "Ans:\r\n" );
document.write( "Let the fraction be x/y\r\n" );
document.write( "The first statement tells us that \r\n" );
document.write( "i.e \r\n" );
document.write( "Simplifying\r\n" );
document.write( " ----> (1)\r\n" );
document.write( "The second statement tells us that \r\n" );
document.write( "i.e. \r\n" );
document.write( "Simplifying\r\n" );
document.write( " -----> (2)\r\n" );
document.write( "The set of 2 simultaneous equations (1) and (2) can be solved using the solver available in this site, as shown below.\r\n" );
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document.write( "Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:\r\n" );
document.write( "  We'll use substitution. After moving -5*y to the right, we get:\r\n" );
document.write( "  , or . Substitute that\r\n" );
document.write( "  into another equation:\r\n" );
document.write( "   and simplify: So, we know that y=5. Since , x=3.\r\n" );
document.write( "  \r\n" );
document.write( "  Answer: .\r\n" );
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document.write( "We get the solution as x = 3, y = 5\r\n" );
document.write( "Hence the fraction is \r\n" );
document.write( "Check: Adding 2 to numerator and denominator, we get 5/7\r\n" );
document.write( "Subtracting 1 from denominator, the fraction becomes 3/4. Correct!\r\n" );
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document.write( "Hope this helps :)\r\n" );
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