document.write( "Question 869745: It took a cyclist 6 hours to travel 48 miles going against the wind. The next day on the return trip, it took the cyclist 3 hours traveling with the wind. What was the speed of the cyclist? \n" ); document.write( "
Algebra.Com's Answer #524372 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed of cyclist = x \n" ); document.write( "speed of wind = y\r \n" ); document.write( "\n" ); document.write( "with wind speed = x+y \n" ); document.write( "against wind speed = x-y\r \n" ); document.write( "\n" ); document.write( "d=rt \n" ); document.write( "d is same in this case\r \n" ); document.write( "\n" ); document.write( "r=d/t \n" ); document.write( "x-y = 180/6 \n" ); document.write( "x-y=30\r \n" ); document.write( "\n" ); document.write( "x+y=180/3 \n" ); document.write( "x+y=60\r \n" ); document.write( "\n" ); document.write( "solve for x & y \n" ); document.write( "2x=90 \n" ); document.write( "x=45 \n" ); document.write( "y=15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |