document.write( "Question 869742: Okay well I have broken down the equation of
\n" ); document.write( "Y=-5x^2+30x-36
\n" ); document.write( "Down to
\n" ); document.write( "Y=-5(x^2-6x)-36
\n" ); document.write( "I'm trying to break it down to standard form.
\n" ); document.write( "Then it's telling me to recall that be constant term in a perfect square is the square of half of the coefficient of the linear term therefore 9 is added inside the parentheses to form a perfect square
\n" ); document.write( "Leaving x^2-6x+9
\n" ); document.write( "My question is where exactly did the 9 come from?
\n" ); document.write( "

Algebra.Com's Answer #524361 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Y=-5x^2+30x-36\r
\n" ); document.write( "\n" ); document.write( "Y=-5(x^2-6x)-36\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Recall (a-b)^2=a^2-2ab+b^2\r
\n" ); document.write( "\n" ); document.write( "we have a^2-2ab\r
\n" ); document.write( "\n" ); document.write( "which is
\n" ); document.write( "x^2-(2)(3)x\r
\n" ); document.write( "\n" ); document.write( "adding 9 will make it a perfect square\r
\n" ); document.write( "\n" ); document.write( "x^2-(2)(3)(3)+9\r
\n" ); document.write( "\n" ); document.write( "we have added 9 so we have to subtract 9\r
\n" ); document.write( "\n" ); document.write( "x^2-6x+9-9\r
\n" ); document.write( "\n" ); document.write( "Finally we have
\n" ); document.write( "y= -5(x^2-6x+9-9) -36\r
\n" ); document.write( "\n" ); document.write( "y=-5((x-3)^2-9)-6^2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );