document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869689>Question 869689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A trucker drove 180 miles to make a delivery and returned home on the same route. Because of foggy conditions, his average speed on the return trip was 10 mph less than his average speed going. If the return trip took 3 hours longer, how fast did he drive in each direction?<BR>\n" );
document.write( "going___________mph<BR>\n" );
document.write( "returning___________mph \r<BR>\n" );
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document.write( "Help me out this is due tomorrow please!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524359 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let forward direction speed =x mph<BR>\n" );
document.write( "return speed = x-10\r<BR>\n" );
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document.write( "180/x = 180/(x-10)-3\r<BR>\n" );
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document.write( "180/(x-10)-180/x =3\r<BR>\n" );
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document.write( "multiply by x(x-10)\r<BR>\n" );
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document.write( "180x-180(x-10)=3x(x-10)\r<BR>\n" );
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document.write( "180x-180x+1800=3x^2-30x\r<BR>\n" );
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document.write( "3x^2-30x-1800=0\r<BR>\n" );
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document.write( "x^2-10x-600=0\r<BR>\n" );
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document.write( "x^2-30x+20x-600=0<BR>\n" );
document.write( "x(x-30)+20(x-30)=0<BR>\n" );
document.write( "(x-30)(x+20)=0<BR>\n" );
document.write( "x=30 taking positive value<BR>\n" );
document.write( "going = 30 mph<BR>\n" );
document.write( "returning = 20 mph </SPAN>\n" );
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