document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869669>Question 869669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3x^2y)(-2xy^5)\r<BR>\n" );
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document.write( "Please simply the exponential expression.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524337 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The idea is to group the like terms together, then multiply them. So 3 and -2 are like terms. They multiply to -6. The terms x^2 and x are like terms, they multiply to x^3, etc etc\r<BR>\n" );
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document.write( "(3x^2y)(-2xy^5)\r<BR>\n" );
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document.write( "(3*(-2)) * (x^2*x) * (y*y^5)\r<BR>\n" );
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document.write( "(-6) * (x^2*x) * (y*y^5)\r<BR>\n" );
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document.write( "(-6) * (x^2*x^1) * (y^1*y^5)\r<BR>\n" );
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document.write( "(-6) * x^(2+1) * y^(1+5)\r<BR>\n" );
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document.write( "<font color=\"red\">-6*x^3*y^6</font> </SPAN>\n" );
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