document.write( "Question 869685: cosx-2sinx^2+1=0 \n" ); document.write( "
Algebra.Com's Answer #524331 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! cosx-2sinx^2+1=0 \n" ); document.write( "------------------- \n" ); document.write( "cos(x) - 2(1-cos^2(x))+1 = 0 \n" ); document.write( "------- \n" ); document.write( "cos(x) -2 + 2cos^2(x) +1 = 0 \n" ); document.write( "------ \n" ); document.write( "2cos^2(x) + x -1 = 0 \n" ); document.write( "------- \n" ); document.write( "Factor: \n" ); document.write( "(2cos(x)-1)(cos(x)+1) = 0 \n" ); document.write( "----- \n" ); document.write( "cos(x) = 1/2 or cos(x) = -1 \n" ); document.write( "---- \n" ); document.write( "x = +-pi/3 or x = pi \n" ); document.write( "---------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------ \n" ); document.write( " |