document.write( "Question 869410: log base 2 (y+6)+log base 2(y-1)=1+log base 2 (3y) \n" ); document.write( "

Algebra.Com's Answer #524275 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%282%2C%28y%2B6%29%29%2Blog%282%2C%28y-1%29%29=1%2Blog%282%2C%283y%29%29\"$
\n" ); document.write( " $\"log%282%2C%28%28y%2B6%29%28y-1%29%29%2F%283y%29%29=1\"$
\n" ); document.write( " $\"%28%28y%2B6%29%28y-1%29%29%2F%283y%29=2\"$
\n" ); document.write( " $\"%28%28y%2B6%29%28y-1%29%29=6y\"$
\n" ); document.write( " $\"y%5E2-y%2B6y-6=6y\"$
\n" ); document.write( " $\"y%5E2-y-6=0\"$
\n" ); document.write( " $\"%28y-3%29%28y%2B2%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"y-3=0\"$
\n" ); document.write( " $\"y=3\"$
\n" ); document.write( "and
\n" ); document.write( " $\"y%2B2=0\"$
\n" ); document.write( " $\"y=-2\"$
\n" ); document.write( "The second solution would not work since $\"log%282%2C%28-3%29%29\"$ and $\"log%282%2C%28-6%29%29\"$
\n" ); document.write( "are not defined.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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