document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869429>Question 869429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2=(2L^-0.5)*20-((4L^0.5)/2)\r<BR>\n" );
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document.write( "Please help me to find L. TQ. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524260 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2=(2L^-0.5)*20-((4L^0.5)/2)<BR>\n" );
document.write( "2 = 40L^-0.5 - 4L^0.5 / 2<BR>\n" );
document.write( "multiply both sides of = by 2<BR>\n" );
document.write( "4 = 80L^-0.5 - 4L^0.5<BR>\n" );
document.write( "divide both sides of = by 4<BR>\n" );
document.write( "1 = 20L^-0.5 - L^0.5<BR>\n" );
document.write( "1 = 20L^0.5 / L - L^0.5<BR>\n" );
document.write( "multiplied 20L^-0.5 by L^0.5/L^0.5<BR>\n" );
document.write( "multiply both sides of = by L<BR>\n" );
document.write( "L = 20L^0.5 - L^3/2<BR>\n" );
document.write( "L^2/2 + L^3/2 = 20L^1/2<BR>\n" );
document.write( "divide both sides of = by L^1/2<BR>\n" );
document.write( "L^1/2 + L = 20<BR>\n" );
document.write( "L = 16\r<BR>\n" );
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