document.write( "Question 869209: You have 180 yards of fencing to use on three sides of a garden. The fourth side is the tool shed.\r
\n" ); document.write( "\n" ); document.write( "a. What is the maximum area that you can fence?
\n" ); document.write( "b. What are the dimensions of the garden?
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Algebra.Com's Answer #524250 by Fombitz(32388)\"\" \"About 
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Let the dimensions of the area be x-y-x where y is the length parallel to the tool shed.
\n" ); document.write( "The area of the rectangle is \"A=xy\"
\n" ); document.write( "The amount of fencing used is \"L=2x%2By=148\"
\n" ); document.write( "Substitute into A,
\n" ); document.write( "\"A=x%28148-2x%29=148x-2x%5E2\"
\n" ); document.write( "To maximize A, find the derivative of area with respect to x.
\n" ); document.write( "\"dA%2Fdx=148-4x=0\"
\n" ); document.write( "\"4x=148\"
\n" ); document.write( "\"x=37\"
\n" ); document.write( "Then
\n" ); document.write( "\"y=148-2%2837%29\"
\n" ); document.write( "\"y=148-74\"
\n" ); document.write( "\"y=74\"
\n" ); document.write( "So,
\n" ); document.write( "a. \"A%5Bmax%5D=37%2A74=2738\"
\n" ); document.write( "b.\"x=37\", \"y=74\"
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\n" ); document.write( "If you had made a semi-circle with the fencing, then
\n" ); document.write( "\"pi%2AR=148\"
\n" ); document.write( "\"R=148%2Fpi\"
\n" ); document.write( "and the area would have been
\n" ); document.write( "\"A=%281%2F2%29pi%2AR%5E2\"}
\n" ); document.write( "\"A=%281%2F2%29pi%2A%28148%5E2%2Fpi%5E2%29\"
\n" ); document.write( "\"A=10952%2Fpi\"
\n" ); document.write( "\"A=3486\" a 27% increase in garden area using the same amount of fence.
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