document.write( "Question 869530: Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation.\r
\n" ); document.write( "\n" ); document.write( "College students' annual earnings: 98% confidence; n = 9, = $3959, s = $886 \n" ); document.write( "

Algebra.Com's Answer #524241 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "ME = 2.33(886/3) = $688.13  (nearest hundred)
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document.write( "CI: μ-ME < u <  μ + ME
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document.write( "CI: $3959-$688 < u <  $3959-$688
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document.write( "Round the confidence interval limits to the same number of decimal places as the sample standard deviation \n" );
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