document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73163>Question 73163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I got this question wrong on a test, so I was just wondering what I did wrong.  Thanks for the help!\r<BR>\n" );
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document.write( "Find the Maximum or minimum value of y=1/3x^2+x+1 and determine for which value of x it occurs\r<BR>\n" );
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document.write( "Thanks again </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52424 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the Maximum or minimum value of y=1/3x^2+x+1 and determine for which value of x it occurs <BR>\n" );
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document.write( "you want to find the axis of symmetry. Using the form y = ax^2 + bx + c,<BR>\n" );
document.write( "the axis of symmetry is found by: x = -b/(2a)<BR>\n" );
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document.write( "In your equation; a = 1/3; b = 1; c = 1 <BR>\n" );
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document.write( "x = -1/(2*(1/3)<BR>\n" );
document.write( "x = -1/(2/3)<BR>\n" );
document.write( "x = -3/2 or -1.5<BR>\n" );
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document.write( "We know it is a minimum, because the coefficient of x^2 is positive<BR>\n" );
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document.write( "to find the vertex, substitute -1.5 in the original equation. </SPAN>\n" );
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