document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869437>Question 869437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angles E and F are complimentary.\r<BR>\n" );
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document.write( "If the measure of angle E = x-10 and the measure of angle F = x+2, find the value of x and the measure of each angle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524239 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since E and F are complementary<BR>\n" );
document.write( "E + F = 90<BR>\n" );
document.write( "(x-10) + (x+2) = 90<BR>\n" );
document.write( "2x -8 = 90<BR>\n" );
document.write( "add 8 to each side<BR>\n" );
document.write( " 2x = 98<BR>\n" );
document.write( "divide each side by 2<BR>\n" );
document.write( " x = 49<BR>\n" );
document.write( "E = x-10 = 49 - 10<BR>\n" );
document.write( "E = 39<BR>\n" );
document.write( "F = x+2 = 49 + 2<BR>\n" );
document.write( "F = 51 </SPAN>\n" );
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