document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73175>Question 73175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If c varies  inversely as d, and if c=12 when d=1/4, find c when d=9?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52422 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If c varies inversely as d, and if c=12 when d=1/4, find c when d=9? \r<BR>\n" );
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document.write( "c = k/d where \"k\" is the constant of variation.<BR>\n" );
document.write( "Find \"k\":<BR>\n" );
document.write( "12 = k/(1/4)<BR>\n" );
document.write( "12=4k<BR>\n" );
document.write( "k=3<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "c = 3/d<BR>\n" );
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document.write( "Now find c if d = <BR>\n" );
document.write( "If d= 9 then <BR>\n" );
document.write( "c = 3/9<BR>\n" );
document.write( "Then c=1/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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