document.write( "Question 869457: seven slips of paper with the numbers 7 through 13 are placed in a box. after mixng well, two slips are drawn. write a sample with equally likely outcomes and find the probability of two even numbers, two odd numbers, and an even number and a odd number. part of the sample space is (7,8),(7,10),(7,11),(7,12),(7,13),(8,10),(8,11),(8,12),(8,13),(9,11),(9,12),(9,13),(10,11),(10,12),(10,13),(11,12),(11,13),(12,13) \n" ); document.write( "

Algebra.Com's Answer #524209 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "7, 8, 9, 10, 11, 12, 13
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document.write( "choose two:
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document.write( "7C2 = 21 in the sample space (assuming Order is not important)
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document.write( "2 Even Sample Space: (8,10),(8,12) (10,12)
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document.write( "P(2 Even) = 3/21 = 1/7
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document.write( "two Odd Sample Space: (7,9), (7,11),(7,13),(9,11), (9,13), (11,13)
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document.write( "P(2 Odd) = 6/21 = 2/7
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document.write( "P(Even and Odd) = 1 - 1/7 - 2/7 = 4/7 \n" );
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