document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=73157>Question 73157</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131808567/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Wizard.7c (may equal earth representative) \"mite b able to find at milkyway - or tha named recordings via:\"The name of the galaxy where 'saturn & Pluto' it's 2007 -by MJG - R a C ~ | 7C, a & b  :  101.7 [ was crakinn ?¢ for knowledge ? In this dimension im the Tormentor - I wonder where the comet went ? <BR>\n" );
document.write( "representin No Limit Soldier A, B & C. The Blue or the Red button ? Life After Death aka the Grim Reaper | Marz: wake the fuk up ai ? | im tha filaus G.'||..||| 'I.D. For Now: GateKeeper C. Just creatin conversation..<BR>\n" );
document.write( "(questions ARE and fuk oath best believe 100% relate to the type of answer displayed to answer the followin question which may seem to b ended with the symbol ---> > >   ?   < < <---#Wizard.7c aka Master Of Dillusiøns | LOL wat might these letters represent via: 1010101 etc<BR>\n" );
document.write( "ns - The Markets is simply the underground ?? •¶ªº•£™ presentin Ao3 - wat the fuks up ???huauhauhuahuhauhauuahahu<BR>\n" );
document.write( "Mwuhauhauhahuauhhuahua put the pieces to the puzzle - piece of piss - need help ?<BR>\n" );
document.write( "How would you write an equation that defys hinted clues to awaken earth's boss ?\r<BR>\n" );
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document.write( "Mana and it's (game theory) media defense mechanism shall now = chosen metafor mages via: drug addic, loopt out type perspective when under the influence of drugs and highness. Think im lying earth ??<BR>\n" );
document.write( "P.S. this may be a legend call for survival - fuk oath cuz___\"\r<BR>\n" );
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document.write( "This may edit the question (Why mentioning this?) - to take back what is mine in relation to the window color 'red' haha. Did i mention this is my dimention - learn about dimensi0nology.. | learn about dinosaur perspectives.. - Media need help ? - Cylone Psycotik R - J & M   . . .    the fukkin red or blue pen ?\r<BR>\n" );
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document.write( "I'm Subject C - the creator's Legend solver - Now awake for the 3rd time or so, sum shit like dat ai ?<BR>\n" );
document.write( "Burmuda's Jafar' </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52416 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the midpoint<BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=Midpoint_of_segment_connecting_two_point.solver>To find midpoint of segment connecting two point</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT> The <A  rel=nofollow HREF=http://www.algebra.com/algebra/about/history/Coordinates-%2528mathematics%2529.wikipedia>Coordinates</A> of mid point of a <A  rel=nofollow HREF=line-ray-and-segments.lesson>line segment</A> joining two points can be calculated using following formulas.<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <b>X coordinate of mid point is</b><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X%5Bmid%5D=+%28X+coordinate_of_first_point+%2B+X+coordinate_of_first_point%29%2F2 ALIGN=MIDDLE  ALT=\"X%5Bmid%5D=+%28X+coordinate_of_first_point+%2B+X+coordinate_of_first_point%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X%5Bmid%5D+=%28-2%2B2%29%2F2 ALIGN=MIDDLE  ALT=\"X%5Bmid%5D+=%28-2%2B2%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X%5Bmid%5D+=%28-2%2B2%29%2F2=0 ALIGN=MIDDLE  ALT=\"X%5Bmid%5D+=%28-2%2B2%29%2F2=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <b>Y coordinate of mid point is</b><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Y%5Bmid%5D=+%28Y+coordinate_of_first_point+%2B+Y+coordinate_of_first_point%29%2F2 ALIGN=MIDDLE  ALT=\"Y%5Bmid%5D=+%28Y+coordinate_of_first_point+%2B+Y+coordinate_of_first_point%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Y%5Bmid%5D+=%280%2B8%29%2F2 ALIGN=MIDDLE  ALT=\"Y%5Bmid%5D+=%280%2B8%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Y%5Bmid%5D=%280%2B8%29%2F2=4 ALIGN=MIDDLE  ALT=\"Y%5Bmid%5D=%280%2B8%29%2F2=4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Hence, The mid point of segment joining two point (-2,0) and (2,8) is (0,4)<BR>\n" );
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document.write( "So the perpendicular line is going to bisect the given segment at the midpoint. Now we must find the slope of the segment<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%288-0%29%2F%282-%28-2%29%29 ALIGN=MIDDLE  ALT=\"m=%288-0%29%2F%282-%28-2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=8%2F4 ALIGN=MIDDLE  ALT=\"m=8%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=2 ALIGN=MIDDLE  ALT=\"m=2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Since a bisected line has a perpendicular bisector, we need a perpendicular slope. So the perpendicular slope is the negative reciprocal of the slope of the given segment<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5Bp%5D=-1%2Fm ALIGN=MIDDLE  ALT=\"m%5Bp%5D=-1%2Fm\"   DISABLED_style= \"max-width:90%; height:auto;\" >where <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5Bp%5D ALIGN=MIDDLE  ALT=\"m%5Bp%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the perpendicular slope<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5Bp%5D=-1%2F2 ALIGN=MIDDLE  ALT=\"m%5Bp%5D=-1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now use the point-slope formula to find the equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-y%5B1%5D=m%28x-x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-4=%28-1%2F2%29%28x-0%29 ALIGN=MIDDLE  ALT=\"y-4=%28-1%2F2%29%28x-0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >Plug in m=-1/2 and (0,4)(the midpoint of the segment)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-4%2B4=%28-1%2F2%29x ALIGN=MIDDLE  ALT=\"y-4%2B4=%28-1%2F2%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" >Add 4 to both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28-1%2F2%29x%2B4 ALIGN=MIDDLE  ALT=\"y=%28-1%2F2%29x%2B4\"   DISABLED_style= \"max-width:90%; height:auto;\" >This is the line that bisects the segment<BR>\n" );
document.write( "Note: you can use winplot (http://math.exeter.edu/rparris/winplot.html) to graph both the line and segment to see if it bisects. </SPAN>\n" );
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