document.write( "Question 869372: Suppose that you have a huge cucumber that is 99% water (by weight). The cucumber weighs 100 pounds. If the water content of the cucumber evaporates until it is 98% water (by weight), then approximately how much does the cucumber now weigh?
\n" ); document.write( "a) 99 pounds
\n" ); document.write( "b) 96 pounds
\n" ); document.write( "c) 95 pounds
\n" ); document.write( "d) 50 pounds
\n" ); document.write( "e) 49 pounds
\n" ); document.write( "f) 98 pounds
\n" ); document.write( "g) 25 pounds
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Algebra.Com's Answer #524148 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Try viewing the cucumber with its solids concentration. 1% solid and 99% water, the typical cucumber.\r
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\n" ); document.write( "\n" ); document.write( "Let x = amount of pounds of material, water, which evaporates from your 100 pound cucumber. The x pounds eveporates until percent solids becomes 2% and water becomes 98%.\r
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\n" ); document.write( "\n" ); document.write( "\"%28100%2A1%29%2F%28100-x%29=2\", the total solid matter stays the same but the x pounds of water leaves.\r
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\n" ); document.write( "\n" ); document.write( "\"100=2%28100-x%29\"
\n" ); document.write( "\"100=200-2x\"
\n" ); document.write( "\"50=100-x\"
\n" ); document.write( "\"50-100=-x\"
\n" ); document.write( "\"x=100-50\"
\n" ); document.write( "\"highlight%28x=50%29\" pounds water.\r
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\n" ); document.write( "\n" ); document.write( "That should not seem strange. Note, this accounts to doubling the concentration of the solid matter of the cucumber. Try a check in the original equation.
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