document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=869302>Question 869302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x) = 2x + 4<BR>\n" );
document.write( "and<BR>\n" );
document.write( "g(x) = 3x - 5\r<BR>\n" );
document.write( "\n" );
document.write( "What would (f - g)(2) = ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #524124 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=524124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since (f - g)(2) = f(2) - g(2), we need the individual values of f(2) and g(2):\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "f(x) = 2x + 4<BR>\n" );
document.write( "f(2) = 2(2) + 4 ... plug in x = 2 and evaluate<BR>\n" );
document.write( "f(2) = 8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "--------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "g(x) = 3x - 5<BR>\n" );
document.write( "g(2) = 3(2) - 5 ... plug in x = 2 and evaluate<BR>\n" );
document.write( "g(2) = 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So,\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(f - g)(2) = f(2) - g(2)<BR>\n" );
document.write( "(f - g)(2) = 8 - 1<BR>\n" );
document.write( "(f - g)(2) = <font color=\"red\">7</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );