document.write( "Question 869304: solve using addition/elimination
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document.write( "x+y+z=0
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document.write( "x-y+4z=17
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document.write( "2x+y+z=-4 \n" );
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Algebra.Com's Answer #524123 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 1 x + 1 y + 1 z = 0 -------------- 1 \n" ); document.write( "1 x + -1 y 4 z = 17 -------------- 2 \n" ); document.write( "2 x + 1 y + 1 z = -4 -------------- 3 \n" ); document.write( " \n" ); document.write( "consider equation 1 &2 Eliminate y \n" ); document.write( "Add the two \n" ); document.write( "2 x + 0 y + 5 z = 17 ------------- 4 \n" ); document.write( "consider equation 2 & 3 Eliminate y \n" ); document.write( " \n" ); document.write( "Add the two \n" ); document.write( "3 x + 0 y + 5 z = 13 -------------5 5 \n" ); document.write( "Consider (4) & (5) Eliminate x \n" ); document.write( "Multiply 4 by -3 \n" ); document.write( "Multiply (5) by 2 \n" ); document.write( "we get \n" ); document.write( "-6 x + -15 z = -51 \n" ); document.write( "6 x + 10 z = 26 \n" ); document.write( "Add the two \n" ); document.write( "0 x + -5 z = -25 \n" ); document.write( "/ -5 \n" ); document.write( "z = 5 \n" ); document.write( "3 x + 5 z= 13 \n" ); document.write( "3 x + 25 = 13 \n" ); document.write( " x = -4 \n" ); document.write( "Plug x & z in eq (1) \n" ); document.write( "1 x + 1 y + 1 z = 0 -------------- 1 \n" ); document.write( " -4 + 1 y + 5 = 0 \n" ); document.write( " 1 y = -1 \n" ); document.write( " y = -1 \n" ); document.write( " x= -4 y= -1 z= 5 \n" ); document.write( " \n" ); document.write( " |